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Find the power of the an electric motor if it lifts 200 kg of water in 5 minutes from a well of 120 m depth. |
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Answer» SOLUTION :Mass of water m = 200 kg , Depth of well = height lifted = 120 m Time `t = 5 xx 60` sec = 300 sec , POWER `= ("Work done against gravitational FORCE")/("time")` Power `= (mgh)/(t) = (200 xx 9.8 xx 120)/(5 xx 60) = 784 W` |
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