Find the precentage degree of dissociation of 0.05 M NH_3 at 25^(@)C in a solutionof pG = 11

Find the precentage degree of dissociation of 0.05 M NH_3 at 25^(@)C i

1.	Find the precentage degree of dissociation of 0.05 M NH_3 at 25^(@)C in a solutionof pG = 11
Answer» Solution :` C = 0.0 5 ,PH = 11 , pOH = 3 ` `rArr [OH^(-)] =10 ^(-3)= CALPHA ` ` rArr alpha = (10^(-3))/(5 XX 10 ^(_2) ) = 2 xx1 0 ^(_2)=2%`