Find the precentage degree of dissociation of 0.05 M NH_3 at 25^(@)C in a solutionof pH = 11

Find the precentage degree of dissociation of 0.05 M NH_3 at 25^(@)C i

1.	Find the precentage degree of dissociation of 0.05 M NH_3 at 25^(@)C in a solutionof pH = 11
Answer» Solution :` C = 0.0 5 ,pH = 11 , pOH = 3 ` `rArr [OH^(-)] =10 ^(-3)= Calpha ` ` rArr alpha = (10^(-3))/(5 xx 10 ^(_2) ) = 2 XX1 0 ^(_2)=2%`