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Find the pressure 200 m below the surface of the ocean if pressure on the free surface of liquid is one atmosphere. (Density of sea water = 1060 kg/m3 ) |
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Answer» Data : h = 200 m, p = 1060 kg/m3 , p0 = 1.013 × 105 Pa, g = 9.8 m/s2 Absolute pressure, p = p0 + hρg = (1.013 × 103 ) + (200)(1060)(9.8) = (1.013 × 105 ) + (20.776 × 105 ) = 21.789 × 105 = 2.1789 MPa |
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