1.

Find the pressure exerted below a column of water, open to the atmosphere, at depth (i) 5 m (ii) 20 m (Given, density of water = `1 xx 10^(3)"kg m"^(-3), g = 10 m s^(-2)`)

Answer» (i) Pressure at a depth of 5 m
`P = P_(a) + rho gh`
`= 1.013 xx 10^(5) Pa + (1 xx 10^(3) kg m^(-3))(10 ms^(-2))(5m)`
`=1.013 xx 10^(5) Pa + 0.5 xx 10^(5) Pa`
`= 1.513 xx 10^(5) Pa`
(ii) Pressure at a depth of 20 m
`P = P_(a) + rho gh`
`= 1.013 xx 10^(5) Pa + (1 xx 10^(3) kg m^(-3))(10 ms^(-2))(20 m)`
`= 1.013 xx 10^(5) Pa + 2 xx 10^(5) Pa`
`= 3.013 xx 10^(5) Pa`
= 3 atm


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