1.

Find the principal value of cot-1(- 1/√3)

Answer»

cot-1(- 1/√3) = π - cot-1(- 1/√3)

[∵ cot-1(-x) = π – cot-1(x)]

= π - π/3

∴ cot-1(- 1/√3) = 2π/3



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