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Find the principal value of each of the following :\(\tan^{-1}\left(\tan\frac{3\pi}{4}\right)\) |
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Answer» \(\tan^{-1}\left(\tan\frac{3\pi}{4}\right)=tan^{-1}\left(\tan\left(\pi-\frac{\pi}{4}\right)\right)\) [Formula: tan(π – x) = -tan (x) , as tan is negative in the second quadrant. ] \(=\tan^{-1}\left(-\tan\frac{\pi}{4}\right)\) [Formula: tan -1(tan x) = x ] =\(-\frac{\pi}{4}\) |
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