Saved Bookmarks
| 1. |
Find the principal value of(i) sin -1 (-1/ √2)(ii) cos -1 (-√3/ 2)(iii) tan -1 (-√3)(iv) sec -1 (-2)(v) cosec -1 (- √2)(vi) cot -1 (-1/ √3) |
|
Answer» (i) sin -1 (-1/ √2) We know that sin -1 (-1/ √2) = – sin -1 (sin π/4) = – π/4 (ii) cos -1 (-√3/ 2) We know that cos -1 (-√3/ 2) = π – cos -1 (cos π/6) = π – π/6 = 5π/6 (iii) tan -1 (-√3) We know that tan -1 (-√3) = – tan -1 (tan π/3) = – π/3 (iv) sec -1 (-2) We know that sec -1 (-2) = π – sec -1 (sec π/3) = π – π/3 = 2 π/3 (v) cosec -1 (- √2) We know that cosec -1 (- √2) = – cosec -1 (cosec π/4) = – π/4 (vi) cot -1 (-1/ √3) We know that cot -1 (-1/ √3) = π – cot -1 (cot π/3) = π – π/3 = 2 π/3 |
|