1.

Find the principal value of:(i) tan -1 (1/√3)(ii) sec -1 (2/√3)(iii) cosec -1 (√2)

Answer»

(i) tan -1 (1/√3)

We know that

tan -1 (1/√3) = tan -1 (tan π/6)

= π/6

(ii) sec -1 (2/√3)

We know that

sec -1 (2/√3) = sec -1 (sec π/6)

= π/6

(iii) cosec -1 (√2)

We know that

cosec -1 (√2) = cosec -1 (cosec π/4)

= π/4



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