Find the principal value of sec−1(2/√3). – InterviewSolution

1.	Find the principal value of sec−1(2/√3).
Answer» Let sec⁻¹(2/√3)=y, then sec=2/√3=(π/6) We know that the range of the principal value branch of sec⁻¹is [0,π]−{π/2} and (π/6)=2/√3. Therefore, the principal value of sec⁻¹(2/√3) is π/6.

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