1.

Find the principal value of tan−1(−√/3).

Answer»

Let tan-1(-√3)=y, then tany=-√3=-tanπ/3=tan(-π/3)

We know that the range of the principal value branch of tan−1 is (-π/2,π/2) and  tan(-π/3)=-√3

Therefore, the principal value of tan-1(-√3) is -π/3.



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