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Find the principal value of tan−1(−√/3). |
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Answer» Let tan-1(-√3)=y, then tany=-√3=-tanπ/3=tan(-π/3) We know that the range of the principal value branch of tan−1 is (-π/2,π/2) and tan(-π/3)=-√3 Therefore, the principal value of tan-1(-√3) is -π/3. |
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