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Find the principal value of the following :\(\cot(\tan^{-1}\mathrm x + \cot^{-1}\mathrm x)\) |
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Answer» \(\cot(\tan^{-1}\mathrm x + \cot^{-1}\mathrm x)=\cot \left(\frac{\pi}{2}\right)\) [ Formula: tan-1 x + cot -1 x = \(\frac{\pi}{2}\)] Putting value of cot\(\left(\frac{\pi}{2}\right)\) =0 |
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