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Find the principal values of each of the following:cot-1(√3) |
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Answer» Let cot–1(√3) = y ⇒ cot y = √3 = cot\((\frac{\pi}6)=\sqrt3\) The range of principal value of cot–1is (0, π) and cot\((\frac{\pi}6)=\sqrt3\) \(\therefore\) The principal value of cot–1(√3) is is \(\frac{\pi}6\) |
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