1.

Find the principle value of the followingsec^(-1)(2/sqrt3)

Answer»

SOLUTION :`SEC(pi/6)=1/(COS(pi/6))=1/((sqrt3/2))=2/sqrt3`and `pi/6 in [0,pi]-{pi/2}`
`therefore The principal value of `sec^(-1)(2/sqrt3)=pi/6`


Discussion

No Comment Found

Related InterviewSolutions