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Find the principle value of the followingsec^(-1)(2/sqrt3) |
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Answer» SOLUTION :`SEC(pi/6)=1/(COS(pi/6))=1/((sqrt3/2))=2/sqrt3`and `pi/6 in [0,pi]-{pi/2}` `therefore The principal value of `sec^(-1)(2/sqrt3)=pi/6` |
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