1.

Find the probability of getting 53 Fridays in a leap year,

Answer»

Leap year = 366 days = (52 × 7 + 2) days = 52 weeks and 2 days.

Thus, a leap year always has 52 Fridays.
The remaining 2 days can be:
(i) Sunday and Monday 

(ii) Monday and Tuesday
(iii) Tuesday and Wednesday 

(iv) Wednesday and Thursday
(v) Thursday and Friday

 (vi) Friday and Saturday
(vii) Saturday and Sunday

Out of these 7 cases, we have Fridays in two cases

P(53 Fridays)=2/7



Discussion

No Comment Found

Related InterviewSolutions