Find the product:(0.8x – 0.5y) (1.5x – 3y)

1.	Find the product:(0.8x – 0.5y) (1.5x – 3y)
Answer» (0.8x – 0.5y) (1.5x – 3y) Suppose (a – b) and (c – d) are two binomials. By using the distributive law of multiplication over addition twice, we may find their product as given below. (a – b) × (c – d) = a × (c – d) – b × (c – d) = (a × c – a × d) – (b × c – b × d) = ac – ad – bc + bd Let, a= 0.8x, b= 0.5y, c= 1.5x, d= 3y Now, = 0.8x × (1.5x – 3y) – 0.5y × (1.5x – 3y) = [(0.8x × 1.5x) + (0.8x × -3y)] – [(0.5y × 1.5x) + (0.5y × -3y)] = [1.2x² – 2.4xy – 0.75yx + 1.5y²] = [1.2x² – 3.15xy + 1.5y²]

Answer»

(0.8x – 0.5y) (1.5x – 3y)

Suppose (a – b) and (c – d) are two binomials. By using the distributive law of multiplication over addition twice, we may find their product as given below.

(a – b) × (c – d) = a × (c – d) – b × (c – d) = (a × c – a × d) – (b × c – b × d)

= ac – ad – bc + bd

Let,

a= 0.8x, b= 0.5y, c= 1.5x, d= 3y

Now,

= 0.8x × (1.5x – 3y) – 0.5y × (1.5x – 3y)

= [(0.8x × 1.5x) + (0.8x × -3y)] – [(0.5y × 1.5x) + (0.5y × -3y)]

= [1.2x² – 2.4xy – 0.75yx + 1.5y²]

= [1.2x² – 3.15xy + 1.5y²]

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