Find the product:(3m – 4n) (2m – 3n)

1.	Find the product:(3m – 4n) (2m – 3n)
Answer» (3m – 4n) (2m – 3n) Suppose (a – b) and (c – d) are two binomials. By using the distributive law of multiplication over addition twice, we may find their product as given below. (a – b) × (c – d) = a × (c – d) – b × (c – d) = (a × c – a × d) – (b × c – b × d) = ac – ad – bc + bd Let, a= 3m, b= 4n, c= 2m, d= 3n Now, = 3m × (2m – 3n) -4n × (2m – 3n) = [(3m × 2m) + (3m × -3n)] – [(4n × 2m) + (4n × -3n)] = [6m² – 9mn – 8mn + 12n²] = [6m² – 17mn + 12n²]

Answer»

(3m – 4n) (2m – 3n)

Suppose (a – b) and (c – d) are two binomials. By using the distributive law of multiplication over addition twice, we may find their product as given below.

(a – b) × (c – d) = a × (c – d) – b × (c – d) = (a × c – a × d) – (b × c – b × d)

= ac – ad – bc + bd

Let,

a= 3m, b= 4n, c= 2m, d= 3n

Now,

= 3m × (2m – 3n) -4n × (2m – 3n)

= [(3m × 2m) + (3m × -3n)] – [(4n × 2m) + (4n × -3n)]

= [6m² – 9mn – 8mn + 12n²]

= [6m² – 17mn + 12n²]

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Find the product:(3m – 4n) (2m – 3n)

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