Find the product:(3p2 + q2) (2p2 – 3q2)

1.	Find the product:(3p2 + q2) (2p2 – 3q2)
Answer» (3p² + q²) (2p² – 3q²) Suppose (a + b) and (c – d) are two binomials. By using the distributive law of multiplication over addition twice, we may find their product as given below. (a + b) × (c – d) = a × (c – d) + b × (c – d) = (a × c – a × d) + (b × c – b × d) = ac – ad + bc – bd Let, a= 3p², b= q², c= 2p², d= 3q² Now, = 3p²× (2p² – 3q²) + q² × (2p² – 3q²) = [(3p²× 2p²) + (3p²× -3q²)] + [(q² × 2p²) + (q² × -3q²)] = [6p⁴ – 9p²q² + 2q²p² – 3q⁴)] = [6p⁴ – 7p²q² – 3q⁴]

Answer»

(3p² + q²) (2p² – 3q²)

Suppose (a + b) and (c – d) are two binomials. By using the distributive law of multiplication over addition twice, we may find their product as given below.

(a + b) × (c – d) = a × (c – d) + b × (c – d) = (a × c – a × d) + (b × c – b × d)

= ac – ad + bc – bd

Let,

a= 3p², b= q², c= 2p², d= 3q²

Now,

= 3p²× (2p² – 3q²) + q² × (2p² – 3q²)

= [(3p²× 2p²) + (3p²× -3q²)] + [(q² × 2p²) + (q² × -3q²)]

= [6p⁴ – 9p²q² + 2q²p² – 3q⁴)]

= [6p⁴ – 7p²q² – 3q⁴]

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Find the product:(3p2 + q2) (2p2 – 3q2)

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