1.

Find the product:(5y – 1) (3y – 8)

Answer»

(5y – 1) (3y – 8)

Suppose (a – b) and (c – d) are two binomials. By using the distributive law of multiplication over addition twice, we may find their product as given below.

(a – b) × (c – d) = a × (c – d) – b × (c – d) = (a × c – a × d) – (b × c – b × d)

= ac – ad – bc + bd

Let,

a= 5y, b= 1, c= 3y, d= 8

Now,

= 5y × (3y – 8) -1 × (3y – 8)

= [(5y × 3y) + (5y × -8)] – [(1 × 3y) + (1 × -8)]

= [15y2 – 40y – 3y + 8]

= [15y2 – 43y + 8]



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