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Find the product:(7/2)x2((4/7)x + 2) |
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Answer» (7/2)x2((4/7)x + 2) Let p, q and r be three monomials. Then, by distributive law of multiplication over addition, we have: P × (q + r) = (p × q) + (p × r) Now, = ((7/2)x2 × (4/7)x) + ((7/2)x2 × 2) = ((7×4)/ (2×7))x3 + ((7×2)/(2×1))x2 … [∵ am × an = am+n] = ((1×2)/ (1×1))x3 + ((7×1)/(1×1))x2 = (2)x3 + (7)x2 |
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