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Find the product:(7/2)x2((4/7)x + 2)

Answer»

(7/2)x2((4/7)x + 2)

Let p, q and r be three monomials.

Then, by distributive law of multiplication over addition, we have:

P × (q + r) = (p × q) + (p × r)

Now,

= ((7/2)x2 × (4/7)x) + ((7/2)x2 × 2)

= ((7×4)/ (2×7))x3 + ((7×2)/(2×1))x2 … [∵ am × an = am+n]

= ((1×2)/ (1×1))x3 + ((7×1)/(1×1))x2

= (2)x3 + (7)x2



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