1.

Find the product by suitable rearrangement:a. 2 × 1768 × 50 = (2 × 50) × 1768b. 4 × 166 × 25 = (4 × 25) × 166c. 8 × 291 × 125 = (8 × 125) × 291d. 625 × 279 × 16 = (625 × 16) × 279e. 285 × 5 × 60 = 285 × 5 × 60f. 125 × 40 × 8 × 25 = 125 × 8 × 40 × 25

Answer»

a. 2 × 1768 × 50 = (2 × 50) × 1768

= 100 × 1768 = 176800

b. 4 × 166 × 25 = (4 × 25) × 166

= 100 × 166 = 16600

c. 8 × 291 × 125 = (8 × 125) × 291

= 1000 × 291 = 291000

d. 625 × 279 × 16 = (625 × 16) × 279

= 10000 × 279 = 2790000

e. 285 × 5 × 60 = 285 × 5 × 60 

= 285 × (5 × 60) = 285 × 300 = 85,500

f. 125 × 40 × 8 × 25 = 125 × 8 × 40 × 25 

= (125 × 40) × (8 × 25) (5000) × (200)

= 1000 × 1000 = 10,00,000.



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