Find the product:(x3 – y3) (x2 + y2)

1.	Find the product:(x3 – y3) (x2 + y2)
Answer» (x³ – y³) (x² + y²) Suppose (a – b) and (c + d) are two binomials. By using the distributive law of multiplication over addition twice, we may find their product as given below. (a – b) × (c + d) = a × (c + d) – b × (c + d) = (a × c + a × d) – (b × c + b × d) = ac + ad – bc – bd Let, a= x³, b= y³, c= x², d= y² Now, = x³ × (x² + y²) – y³ × (x² + y²) = [(x³ × x²) + (x³ × y²)] – [(y³ × x²) + (y³ × y²)] = [x⁵ + x³y² – y³x² – y⁵]

Answer»

(x³ – y³) (x² + y²)

Suppose (a – b) and (c + d) are two binomials. By using the distributive law of multiplication over addition twice, we may find their product as given below.

(a – b) × (c + d) = a × (c + d) – b × (c + d) = (a × c + a × d) – (b × c + b × d)

= ac + ad – bc – bd

Let,

a= x³, b= y³, c= x², d= y²

Now,

= x³ × (x² + y²) – y³ × (x² + y²)

= [(x³ × x²) + (x³ × y²)] – [(y³ × x²) + (y³ × y²)]

= [x⁵ + x³y² – y³x² – y⁵]

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Find the product:(x3 – y3) (x2 + y2)

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