Find the products: ((1/2) y2 – (1/3) y) ((1/2) y2 – (1/3)y)

1.	Find the products: ((1/2) y2 – (1/3) y) ((1/2) y2 – (1/3)y)
Answer» Given that ((1/2) y² – (1/3) y) ((1/2) y² – (1/3) y) But we can write the given expression as ((1/2) y² – (1/3) y) ((1/2) y² – (1/3) y) = ((1/2) y² – (1/3) y)² But we have (a – b)²=a²-2ab+b² On applying above identity in the given expression we get, ((1/2) y² – (1/3) y)²= ((1/4) y²-2 ((1/2) y) (1/3) + (1/3) y² ((1/2) y² – (1/3) y)²= ((1/4) y²– y (1/3) + (1/9) y²

Answer»

Given that ((1/2) y² – (1/3) y) ((1/2) y² – (1/3) y)

But we can write the given expression as

((1/2) y² – (1/3) y) ((1/2) y² – (1/3) y) = ((1/2) y² – (1/3) y)²

But we have (a – b)²=a²-2ab+b²

On applying above identity in the given expression we get,

((1/2) y² – (1/3) y)²= ((1/4) y²-2 ((1/2) y) (1/3) + (1/3) y²

((1/2) y² – (1/3) y)²= ((1/4) y²– y (1/3) + (1/9) y²

Discussion