Find the products:(-1/27)a2b2 × (-9/2)a3bc2

1.	Find the products:(-1/27)a2b2 × (-9/2)a3bc2
Answer» (-1/27)a²b² × (-9/2)a³bc² The coefficient of the product of two monomials is equal to the product of their coefficients. The variable part in the product of two monomials is equal to the product of the variables in the given monomials. Then, = [(-1/27) × (-9/2)] × (a²× a³) × (b² × b) × c² = [(-1×-9)/ (27×2)] × (a²⁺³) × (b²⁺¹) × c² … [∵ a^m × aⁿ = a^m+n] = [(-1×-1)/ (3×2)] × (a⁵) × (b³) × c² = [1/6]a⁵b³c²

Answer»

(-1/27)a²b² × (-9/2)a³bc²

The coefficient of the product of two monomials is equal to the product of their coefficients.

The variable part in the product of two monomials is equal to the product of the variables in the given monomials.

Then,

= [(-1/27) × (-9/2)] × (a²× a³) × (b² × b) × c²

= [(-1×-9)/ (27×2)] × (a²⁺³) × (b²⁺¹) × c² … [∵ a^m × aⁿ = a^m+n]

= [(-1×-1)/ (3×2)] × (a⁵) × (b³) × c²

= [1/6]a⁵b³c²

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