Find the products:(-13/5)ab2c × (7/3)a2bc2

1.	Find the products:(-13/5)ab2c × (7/3)a2bc2
Answer» (-13/5)ab²c × (7/3)a²bc² The coefficient of the product of two monomials is equal to the product of their coefficients. The variable part in the product of two monomials is equal to the product of the variables in the given monomials. Then, = [(-13/5) × (7/3)] × (a × a²) × (b² × b) × (c × c²) = [(-13×7)/ (5×3)] × (a¹⁺²) × (b²⁺¹) × (c¹⁺²) … [∵ a^m × aⁿ = a^m+n] = [-91/ 15] × (a³) × (b³) × c³ = [-91/15]a³b³c³

Answer»

(-13/5)ab²c × (7/3)a²bc²

The coefficient of the product of two monomials is equal to the product of their coefficients.

The variable part in the product of two monomials is equal to the product of the variables in the given monomials.

Then,

= [(-13/5) × (7/3)] × (a × a²) × (b² × b) × (c × c²)

= [(-13×7)/ (5×3)] × (a¹⁺²) × (b²⁺¹) × (c¹⁺²) … [∵ a^m × aⁿ = a^m+n]

= [-91/ 15] × (a³) × (b³) × c³

= [-91/15]a³b³c³

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