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Find the products:(2/3)x2y × (3/5)xy2 |
Answer» (2/3)x2y × (3/5)xy2 The coefficient of the product of two monomials is equal to the product of their coefficients. The variable part in the product of two monomials is equal to the product of the variables in the given monomials. Then, = [(2/3) × (3/5)] × (x2 × x) × (y × y2) = [(2×3)/ (3×5)] × (x2+1) × (y1+2) … [∵ am × an = am+n] = [(2×1)/ (1×5)] × (x3) × (y3) = [2/5]x3y3 |
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