Find the purity percentage of conc. h2so4 with density 1.8, if 5ml of

1.	Find the purity percentage of conc. h2so4 with density 1.8, if 5ml of h2so4 is neutralised completely by 84.6 ml of 2n NaOH solution ?
Answer» Answer: N1V1 = N2V2 N1=? V1=5 N2=2 V2=84.6 Apply into the equation N15 = 84.62 N1 = 84.62/5 = 33.84 N M = 33.84/2 = 16.92 M 16.92 moles of H2SO4 is present in the 1000 ml of the soln. Density = mass/volume then, mass = density x volume = 1.81000 = 1800g. hence the mass of H2SO4 =16.9298 = 1658.16g. Percentage PURITY of H2SO4 = (1658.16/1800)100 = 92.12% THEREFORE the percentage purity for the H2SO4 in the SOLUTION is 92% approximately Explanation: here is your answer

Find the purity percentage of conc. h2so4 with density 1.8, if 5ml of h2so4 is neutralised completely by 84.6 ml of 2n NaOH solution ?

Answer»

Answer:

N1V1 = N2V2

N1=?

V1=5

N2=2

V2=84.6

Apply into the equation

N1*5 = 84.6*2

N1 = 84.6*2/5 = 33.84 N

M = 33.84/2 = 16.92 M

16.92 moles of H2SO4 is present in the 1000 ml of the soln.

Density = mass/volume then,

mass = density x volume = 1.8*1000 = 1800g.

hence the mass of H2SO4 =16.92*98 = 1658.16g.

Percentage PURITY of H2SO4 = (1658.16/1800)*100 = 92.12%

THEREFORE the percentage purity for the H2SO4 in the SOLUTION is 92% approximately

Explanation:

here is your answer