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Find the quadratic polynomial, sum of whose zeroes is 5/2 and their product is 1. Hence, find the zeroes of the polynomial. |
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Answer» Given : Sum of zeroes = (∝ + β) = 5/2 Product of the zeroes = = 1 Required quadratic polynomial is x2 – (∝+β)x + ∝β = x2 – (5/2)x + 1 = 1/2(2x2 – 5x + 2) Now, find the zeroes of the above polynomial. Let f(x) = 1/2(2x2 – 5x + 2) = 1/2(2x2 – 4x – x + 2) = 1/2(2x(x – 2) – (x – 2)) = 1/2( (2x – 1)(x – 2) ) Substitute f(x) = 0. 1/2( (2x – 1)(x – 2) ) = 0 either (2x – 1) = 0 or (x – 2) = o x = 1/2 or x = 2 1/2 and 2 are the zeroes of the polynomial. |
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