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Find the quadratic polynomial, sum of whose zeroes is 8 and their product is 12. Hence, find the zeroes of the polynomial. |
Answer» Given : Sum of zeroes = (∝ + β) = 8 Product of the zeroes = = 12 Required quadratic polynomial is x2 – (∝+β)x + ∝β = x2 – (8)x + 12 Now, find the zeroes of the above polynomial. Let f(x) = x2 – (8)x + 12 = x2 – 6x – 2x + 12 = (x -6)(x – 2) Substitute f(x) = 0. either (x -6) = 0 or (x – 2) = 0 x = 6 or x = 2 2 and 6 are the zeroes of the polynomial. |
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