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Find the quadratic polynomial whose zeroes are 2 and -6. Verify the relation between the coefficients and the zeroes of the polynomial. |
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Answer» Let α = 2 and β = - 6 Sum of the zeroes, (α+ β) = 2 + (- 6) = - 4 Product of the zeroes,αβ = 2 × (-6) = -12 ∴ Required polynomial = x2 - (α +β)x + αβ = x2 – (- 4)x – 12 = x2 + 4x – 12 Sum of the zeroes = -4 = \(\frac{-4}1\) = \(\frac{-(coefficient\,of\,x)}{(coefficient\,of\,x^2)}\) Product of zeroes = -12 = = \(\frac{-12}1\) = \(\frac{constant\,term}{(coefficient\,of\,x^2)}\) |
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