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Find the quadratic polynomial whose zeroes are 2 and -6. Verify the relation between the coefficients and the zeroes of the polynomial. |
Answer» Let ∝ = 2 and β = -6 Sum of the zeroes = (∝ + β) = 2 – 6 = -4 Product of the zeroes, = 2(-6) = -12 Required quadratic polynomial is x2 – (∝+β)x + ∝β = x2 – (-4)x – 12 = x2 + 4x – 12 And, Sum of the zeroes = – 4 = -4/1 = (-Coefficient of x)/(Cofficient of x2) Product of zeroes = -12 = -12/1 = Constant term / Coefficient of x2 |
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