Find the quantity of charge require for the decomposition of 3.6g of w

1.	Find the quantity of charge require for the decomposition of 3.6g of water
Answer» Gram atomic mass of WATER (H2O) = (1×2+16) gm = (2+16) gm = 18 gm ∴ Number of molecules in 18 gm of water = 1 MOL ∴ Number of MOLECULE in 1 gm of water = 1/18 mol ∴ Number of molecule in 3.6 gm of water = (1/18 X 3.6)mol = 0.2 molExplanation:

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