1.

Find the radius of the soap bubble if 44xx10^(-6)J of work is done in blowing the soap bubble. Surface tension of soap solution = 7xx10^(-2)Nm^(-1)

Answer»

Solution :Work done, `W=44xx10^(-6)J`
If .r. is the radius of the SOAP bubble
Surface area of the soap bubble = `8pir^(2)`
Work done in BLOWING soap bubble (W) = surface area of the bubble x surace tension `W=8pir^(2)`. S
`therefore r^(2)=(W)/(8piS)`
`r=sqrt((W)/(8piS))=sqrt((44xx10^-6)/(8xx(22)/(7)xx7xx10^-2))`
`=sqrt((1)/(4)xx10^(-4)),"r = 0.005m (or) 5MM"`


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