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Find the range of f(x) = 2(x+3)/3. |
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Answer» \(f(x)=\frac{2(x +3)}{3}\) \(\because\) function f(x) is defined for all real values of x. \(\therefore\) \(- \infty < x< \infty\) ⇒ \(- \infty < x +3 < \infty\) ⇒ \( - \infty <\frac{2(x +3)}{3} < \infty\) ⇒ \(- \infty < f(x) < \infty\) Range of function f(x) is \(\mathbb {R}\) or \((-\infty, \infty)\). |
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