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Find the range of function `y=ln(2 x-x^(2))` |
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Answer» Step-1 We have `2x-x^(2)epsilon(-oo,1]` Step -2 Let `t=2x-x^(2)` for `lnt` to be defined accepted values are `(0,1]` Now, using monotonicity of `lnt`, `ln(2x-x^(2))epsilon(-oo,0]` `:.` range is `(-oo,0]` |
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