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Find the rank of A = \( \begin{bmatrix} 4 & 5 & -6 & -1 \\ 7 & -3 & 0 & 8\\ \end{bmatrix} \) |
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Answer» Given A = \(\begin{bmatrix}4 & 5 & -6 & -1 \\7 & -3 & 0 & 8\\\end{bmatrix}\) Consider the minor \(\begin{vmatrix}5 & -6 \\-3 & 0\end{vmatrix}\) = -18 \(\ne\) 0 Since a minor of order 2 is not zero, rank is 2 |
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