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Find the rate at which the volume of a spherical balloon will increase when its radius is 2 meters if the rate of increase of its redius is 0.3 m/min. |
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Answer» Solution :Let r be the radius of a spherical ballon. Give that dr/dt = 0.3 m/min. If V be the volume of the ballon then `dV/dt = 3/4 PI r _3`. `rArr Dv/dt = 3/4 pi cdot 3r^2 dr/dt = 4 pi r^2 dr/dt` `therefore Dv/dt](r=2) = 4pi xx4 XX cdot 3 = 4 cdot 8 pi m^3/min` `therefore` The volume increase at the rate of `4 cdot 8 pi m^3/min`. |
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