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| 1. |
Find the rate of change of the area of circle w.r.t.r when r=8 cm. |
| Answer» SOLUTION :Let radius =R cm. `therefore` AREA of the CIRCLE `A=pir^2rArr(dA)/dr=2pir` The RATE of change of area for r=8 is `(dA)/(dr)]_(r=8)=[2pir]_(r=8)=16picm^2//cm` | |