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Find the ratio between two numbers such that their sum is 40 and their difference is 8. |
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Answer» Let the two numbers be x & y Given x + y = 40 ……. (1) & x – y = 8 … (2) Solving we get Adding 2x = 48 ⇒ x = 24 & y = 40 – 24 = 16 ∴ Ratio of the numbers is 24 : 16 ⇒ 3:2. |
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