Find the ratio of escape velocities from the earth and the moon. (Mass of the earth = 6.0 xx 10^(24) kg, Radius of the earth = 6400 km, Mass of the moon = 7.4 xx 10^(22) kg Radius of the moon = 1740 km.)

Find the ratio of escape velocities from the earth and the moon. (Mass

1.	Find the ratio of escape velocities from the earth and the moon. (Mass of the earth = 6.0 xx 10^(24) kg, Radius of the earth = 6400 km, Mass of the moon = 7.4 xx 10^(22) kg Radius of the moon = 1740 km.)
Answer» <html><body><p></p>Solution :`V_(e) prop <a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>((M)/(R))` <br/> `(V_(e1))/(V_(<a href="https://interviewquestions.tuteehub.com/tag/e2-961697" style="font-weight:bold;" target="_blank" title="Click to know more about E2">E2</a>)) = sqrt(((6.0xx 10^(24))/(7.4 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 10^(<a href="https://interviewquestions.tuteehub.com/tag/22-294057" style="font-weight:bold;" target="_blank" title="Click to know more about 22">22</a>)))((1740)/(6400))) = (4.695)/(1)`</body></html>