Saved Bookmarks
| 1. |
Find the ratio of escape velocities of two planets if values of g on the two planets are 9.8 m//s^(2) and 3.3 m//s^(2) and ther radii are 6400 km and 3400 km respectively. |
|
Answer» Solution :The ESCAPE velocity in TIMES of g and R is The ratio of escape velocities `(V_(E1))/(V_(E2)) = sqrt((g_(1)R_(1))/(g_(2)R_(2)))` `(V_(e1))/(V_(e2)) = sqrt(((9.8)/(3.3))((6400)/(3400))) = (2.364)/(1)` `V_(e1) : V_(e2) = 2.364:1`. |
|