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Find the ratio of the orbital speed of two satellites one of which is rotating round the earth and the other around Mars close to their surface . (mass of the earth = 6.4xx10^(23) kg. Mass of the Mars= 6.4xx10^(23)Radius of the earth = 6400km and Radius of Mars= 3400km) |
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Answer» SOLUTION :The orbital speed of a satellite close to the SURFACE of a planet, `V_(0)=sqrt((GM)/R)` The RATIO orbital speeds , `V_(01)/V_(02) = V_(01)/V_(02)sqrt(((M_1)/M_2)((R_2)/(R_1)))` `V_(01)/V_(02)sqrt(((6xx10^(24))/(6.4xx10^(23)))((3400)/(6400)))=sqrt((60xx34)/(6.4xx64))=(2.232)/1` |
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