1.

Find the ratio of the orbital speeds to two satellites one of which is rotating round the earth and the other around Mars close to their surface. (mass of the earth = 6 xx 10^(24) kg, Mass of the Mars = 6.4 xx 10^(23)kg, Radius of the earth = 6400 km and radius of Mars = 3400 km)

Answer»

Solution :The orbital speed of a SATELLITE close to the surface of a PLANET,
`V_(0) = sqrt((GM)/(R))`
The ratio of orbital speeds,
`(V_(01))/(V_(02)) = sqrt(((M_(1))/(M_(2)))((R_(2))/(R_(1))))`
`(V_(01))/(V_(02)) = sqrt(((6 xx 10^(24))/(6.4 xx 10^(23)))((3400)/(6400)))`
`= sqrt((60 xx 34)/(6.4 xx 64)) = (2.232)/(1)`


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