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Find the ratio of wavelengths of first line of Lyman series and second line of Balmer series |
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Answer» Use Rydberg formula `1/(lambdak_alpha)=R_H(1/1^2-1/2^2)` `1/(lambda_(Lbeta))=R_H(1/2^2-1/4^2)` `(lambda_(kalpha))/(lambda_(Lbeta))=((16-4)xx4xx1)/(4xx16(4-1))` `=12/(16xx3)=1/4` |
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