1.

Find the reading of the ammeter when the voltmeter across the 3 ohm resistor in the circuit of Fig.  reads 45 V.

Answer»

Obviously I1 = 45/3 = 15A. If we take it as reference quantity, I1 = 3 ∠0º

Now, Z1 = 3 −j3 = 4.24 ∠− 45º. 

Hence, V = I1Z1 = 15 ∠0º × 4.24 ∠−45º = 63.6 ∠−45º

I2 = V/Z2 = (63.6 ∠ -45º)/(5 + j2) = (63.6 ∠-45º)/(5.4 ∠ 21.8º)

= 11.77 ∠ − 66.8º = 4.64 − j10.8

I = I1 + I2 = 19.64 −j10.8 = 22.4 ∠28.8º



Discussion

No Comment Found

Related InterviewSolutions