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find the real value of 3x+y-4i=5+(2x-3y)i

Answer» (3x + y)+(-4)i=(5)+(2x-3y)iComparing real and imaginary parts,we have•3x+y=5------{a}•2x-3y=-4-------{b}Now,{a}=> y=5-3x{b}=> 2x-3(5-3x)=-4 => 2x-15+9x=-4 => 11x=-4+15=11 => x=1 Therefore, y=5-3x=5-(3×1)=2. Solution, x=1,y=2.


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