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Find the relation between the root and coefficient of x3 - 6x2 + 11x - 6. |
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Answer» \(x^3 - 6x^2 + 11x -6 = 0\) Let roots are \(\alpha, \beta\) and \(\gamma\). Then sum of roots = \(\alpha + \beta + \gamma = \frac{-b}a = \frac{-(-6)}1 = 6\) Sum of products of two roots = \(\alpha\beta + \beta\gamma + \alpha\gamma = \frac ca = \frac{11}1 = 11\) Product of roots = \(\alpha \beta\gamma = \frac{-d}a = \frac{-(-6)}1 = 6\). |
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