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Find the relative error in Z, if `Z=A^(4)B^(1//3)//CD^(3//2)`.A. `(DeltaZ)/(Z)=4(DeltaA)/(A)+(1)/(3)(DeltaB)/(B)+(DeltaC)/(C)+(3)/(2)(DeltaD)/(D)`B. `(DeltaZ)/(Z)=4(DeltaA)/(A)+(1)/(3)(DeltaB)/(B)-(DeltaC)/(C)-(3)/(2)(DeltaD)/(D)`C. `(DeltaZ)/(Z)=4(DeltaA)/(A)+(1)/(3)(DeltaB)/(B)+(DeltaC)/(C)-(3)/(2)(DeltaD)/(D)`D. `(DeltaZ)/(Z)=4(DeltaA)/(A)+(1)/(3)(DeltaB)/(B)-(DeltaC)/(C)+(3)/(2)(DeltaD)/(D)` |
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Answer» Correct Answer - A `Z=(A^(4)B^(1//3))/(CD^(3//2))`. The relative error in Z is given by `(DeltaZ)/(Z)=4(DeltaA)/(A)+(1)/(3)(DeltaB)/(B)+(DeltaC)/(C)+(3)/(2)(DeltaD)/(D)` |
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