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Find the relative error z if z=a^3b^6/√dc |
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Answer» Hlo $$3(\\frac{\\Delta a}{a})+6(\\frac{\\Delta b}{b})+\\frac{1}{2}(\\frac{\\Delta d}{d})+1(\\frac{\\delta c}{c})$$ $$3(\\frac{∆a}{a})+6(\\frac{∆b}{b})+\\frac{1}{2}(\\frac{∆d}{d})+1(\\frac{∆c}{c})$$ |
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