1.

Find the remainder of (3^(9415))/(80).

Answer»

Solution :REM `3^9415/80=Rem(3^9412xx3^3)/80`
=Rem `(3^4)^2353xx3^3/80`
=Rem `(81^2353)xx3^3/80`=Rem`1xx27/80`=Rem27/80`
THUS the remainder is 27.


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